python实现的简单文本类游戏实例

本文实例讲述了python实现的简单文本类游戏实现方法。分享给大家供大家参考。具体实现方法如下：

    ############################################################
    # - My version on the game "Dragon Realm".
    # - taken from the book "invent with python" by Al Sweigart.
    # - thanks for a great book Mr Sweigart.
    # - this code takes advantage of python 3.
    ############################################################
    #files.py
    import random
    import time
    print('\n\n[--system--] one file is bad the other is good ..guess the right one.\n')
    print('\n\nconnecting....')
    time.sleep(1)
    print('....')
    time.sleep(1)
    print('....')
    time.sleep(1)
    print('....')
    time.sleep(1)
    print('\nconnection established')
    def displayIntro():
      print('------------')
      print('SYSTEM FILES')
      print('------------\n')
      print('1.) file.')
      print('2.) file.\n')
    def chooseOption():
      option = ''
      while option != '1' and option != '2':
        print('which file to download? 1 or 2')
        option = input('user:> ')
      return option
    def checkOption(chosenOption):
      print('\nintialising download....')
      time.sleep(1)
      print('accessing file....')
      time.sleep(1)
      print('downloading....')
      time.sleep(1)
      print('....')
      time.sleep(1)
      print('....')
      time.sleep(1)
      goodfile = random.randint(1, 2)
      if chosenOption == str(goodfile):
        print('\ndownload complete.')
        print('\nGAME OVER')
      else:
        print('\nfile corrupt')
        print('system infected.')
        print('\nGAME OVER')
    playAgain = 'yes'
    while playAgain == 'yes':
      displayIntro()
      optionNumber = chooseOption()
      checkOption(optionNumber)
      print('\ndownload again? .... (yes or no)')
      playAgain = input('user:> ')

    ############################################################
    # - My version of the game "guess the number".
    # - taken from the book "invent with python" by Al Sweigart.
    # - thanks for a great book Mr Sweigart.
    # - this code takes advantage of python 3.
    ############################################################
    # -NOTE - this program will crash if a number is not typed.
    #digitcode.py
    import random
    import time
    guessesTaken = 0
    print('\n\n\n\n\n[--system--] enter code in 15 trys to avoid lockout\n')
    print('\nconnecting....')
    time.sleep(1)
    print('....')
    time.sleep(1)
    print('....')
    time.sleep(1)
    print('....')
    time.sleep(1)
    print('connection established\n')
    print('---------------------')
    print(' MAINFRAME - LOGIN ')
    print('---------------------')
    print('\nenter 3 digit access code..')
    number = random.randint(000, 999)
    while guessesTaken < 15:
      print()
      guess = input('user:> ')
      guess = int(guess)
      guessesTaken = guessesTaken + 1
      if guess < number:
        print('\nACCESS - DENIED -code to low')
      if guess > number:
        print('\nACCESS - DENIED -code to high')
      if guess == number:
        break
    if guess == number:
      guessesTaken = str(guessesTaken)
      print('\nverifying ....')
      time.sleep(1)
      print('\nauthenticating ....')
      time.sleep(1)
      print('....')
      time.sleep(1)
      print('....')
      time.sleep(1)
      print('\nACCESS - GRANTED')
      print('\nGAME OVER\n')
      exit(0)
    if guess != number:
      number = str(number)
      print('\n....')
      time.sleep(1)
      print('\n....')
      time.sleep(1)
      print('\nSYSTEM LOCKED -the code was ' + number)
      print()
      exit(0)

希望本文所述对大家的Python程序设计有所帮助。