Python实现列表转换成字典数据结构的方法

本文实例讲述了Python实现列表转换成字典数据结构的方法。分享给大家供大家参考，具体如下：

    '''
    [
      {'symbol': 101, 'sort': 1, 'name': 'aaaa'},
      {'symbol': 102, 'sort': 2, 'name': 'bbbb'},
      {'symbol': 103, 'sort': 3, 'name': 'cccc'},
      {'symbol': 104, 'sort': 4, 'name': 'dddd'},
      {'symbol': 105, 'sort': 5, 'name': 'eeee'},
      {'symbol': 106, 'sort': 6, 'name': 'ffff'},
      {'symbol': 107, 'sort': 7, 'name': 'gggg'},
      {'symbol': 108, 'sort': 8, 'name': 'hhhh'},
      {'symbol': 109, 'sort': 9, 'name': 'iiii'}
    ]
    转换成如下的结构，便于通过ID获取记录值
    {
      101: {'sort': 1, 'symbol': 101, 'name': 'aaaa'},
      102: {'sort': 2, 'symbol': 102, 'name': 'bbbb'},
      103: {'sort': 3, 'symbol': 103, 'name': 'cccc'},
      104: {'sort': 4, 'symbol': 104, 'name': 'dddd'},
      105: {'sort': 5, 'symbol': 105, 'name': 'eeee'},
      106: {'sort': 6, 'symbol': 106, 'name': 'ffff'},
      107: {'sort': 7, 'symbol': 107, 'name': 'gggg'},
      108: {'sort': 8, 'symbol': 108, 'name': 'hhhh'},
      109: {'sort': 9, 'symbol': 109, 'name': 'iiii'}
    }
    '''
    students = [
        {'symbol': 101, 'sort': 1, 'name': 'aaaa'},
        {'symbol': 102, 'sort': 2, 'name': 'bbbb'},
        {'symbol': 103, 'sort': 3, 'name': 'cccc'},
        {'symbol': 104, 'sort': 4, 'name': 'dddd'},
        {'symbol': 105, 'sort': 5, 'name': 'eeee'},
        {'symbol': 106, 'sort': 6, 'name': 'ffff'},
        {'symbol': 107, 'sort': 7, 'name': 'gggg'},
        {'symbol': 108, 'sort': 8, 'name': 'hhhh'},
        {'symbol': 109, 'sort': 9, 'name': 'iiii'}
      ]
    symbol_list = map(lambda x: (x.get('symbol'), x), students)
    print symbol_list
    print '-----------------------------------------'
    print dict(symbol_list)
    #value_list = map(lambda x: x, students)
    #
    ##print dict(zip(symbol_list, value_list))
    #
    #
    #student = {
    #    101: {'symbol': 101, 'sort': 1, 'name': 'aaaa'}
    #    }
    #
    #student = [
    #    {101: {'symbol': 101, 'sort': 1, 'name': 'aaaa'}}
    #    ]
    #

排序用法：

    students = [
          {'name':'zhangsan', 'price':20.01, 'date':'2015-01-09T01:00:00Z'},
          {'name':'lisi', 'price':10.01, 'date':'2013-01-09T01:00:00Z'},
          {'name':'wangwu', 'price':0.01, 'date':'2012-01-09T01:00:00Z'}
    ] 
    print sorted(students, key=lambda s:s["name"])
    print sorted(students, key=lambda s:s["price"], reverse=True)
    print sorted(students, key=lambda s:s["date"], reverse=True)
    aa = sorted(students, key=lambda s:s["price"], reverse=True)
    sorted(aa, key=lambda s:s["date"], reverse=True)
    symbol_arr = [<Symbol: Symbol object>, <Symbol: Symbol object>, <Symbol: Symbol object>] 
    sorted(symbol_arr, key=lambda s:s.amount, reverse=True)

希望本文所述对大家Python程序设计有所帮助。