python求斐波那契数列示例分享

873次阅读  |  发布于5年以前

复制代码 代码如下:

def getFibonacci(num):
res=[0,1]
a=0
b=1
for x in range(0,num):
if x==a+b:
res.append(x)
a,b=b,a+b
return res

res=getFibonacci(1000)
print(res)

递归

a=[0,1]
qian=0
def fibna(num,qian):
print(num)
he=num+qian
if he<1000:
a.append(he)
qian=num
fibna(he,qian)
fibna(1,0)
print(a)

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