python 计算两个日期相差多少个月实例代码

近期，由于业务需要计算两个日期之前相差多少个月。我在网上找了很久，结果发现万能的python，居然没有一个模块计算两个日期的月数，像Java、C#之类的高级语言，都会有(date1-date2).months的现成方法，觉得不可思议。说句实在的，一直觉得python 的日期处理模块真心不好用。

哦，对了，别跟我说 datetime, calendar, dateutil 这些模块，因为我都试过了，都没用。有个竟然算出来还有错。datetime.timedelta只能计算出日时分秒。对年月却不支持。网上一搜，一大堆的。

dateutil.rrule这个例子是我好不容易找到的，请看我的测试结果：

    import datetime

    from dateutil import rrule

    d1 = datetime.date(2016, 2, 29)
    d2 = datetime.date(2019, 3, 31)

    months = rrule.rrule(rrule.MONTHLY, dtstart=d1, until=d2).count()

    print(f"months={months}")

看到这样的结果，我只能呵呵了。

废话不多少，献上自己写的代码：

该代码返回，（月,小数月）

    import datetime

    import calendar as c



    d1 = datetime.date(2016, 2, 29)

    d2 = datetime.date(2019, 3, 31)



    def calmonths(startdate, enddate):

    # 计算两个日期相隔月差

    samemonthdate = None

    try:

    samemonthdate = datetime.date(enddate.year, enddate.month,

    startdate.day)

    except Exception as e:

    print(e)

    samemonthdate = datetime.date(enddate.year, enddate.month,

    c.monthrange(enddate.year,

    enddate.month)[1])


    holdmonths = 0

    decimalmonth = 0.0

    if samemonthdate > enddate:

    premanthdate = None

    try:

    premanthdate = datetime.date(enddate.year, enddate.month - 1,

    startdate.day)

    except Exception as e:

    print(e)

    premanthdate = datetime.date(enddate.year, enddate.month - 1,

    c.monthrange(

    enddate.year,

    enddate.month - 1)[1])

    currmonthdays = (samemonthdate - premanthdate).days

    holdmonths = (premanthdate.year - startdate.year

    ) * 12 + premanthdate.month - startdate.month

    decimalmonth = (enddate - premanthdate).days / currmonthdays


    elif samemonthdate < enddate:

    nextmonthdate = None

    try:

    nextmonthdate = datetime.date(enddate.year, enddate.month + 1,

    startdate.day)

    except Exception as e:

    nextmonthdate = datetime.date(enddate.year, enddate.month + 1,

    c.monthrange(

    enddate.year,

    enddate.month + 1)[1])

    currmonthdays = (nextmonthdate - samemonthdate).days

    holdmonths = (samemonthdate.year - startdate.year

    ) * 12 + samemonthdate.month - startdate.month

    decimalmonth = (enddate - samemonthdate).days / currmonthdays


    else:

    holdmonths = (enddate.year - startdate.year

    ) * 12 + enddate.month - startdate.month


    return holdmonths, decimalmonth


    months = calmonths(d1, d2)


    print(f"months={months}")

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