有这样一道题目： 字符串标识符.修改例 6-1 的 idcheck.py 脚本,使之可以检测长度为一的标识符,并且可以识别 Python 关键字,对后一个要求,你可以使用 keyword 模块(特别是 keyword.kelist)来帮你.

我最初的代码是：

复制代码 代码如下:

!/usr/bin/env python

import string
import keyword
import sys

Get all keyword for python

keyword.kwlist

['and', 'as', 'assert', 'break', ...]

keyWords = keyword.kwlist

Get all character for identifier

string.letters ==> 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'

string.digits ==> '0123456789'

charForId = string.letters + "_"
numForId = string.digits

idInput = raw_input("Input your words,please!")

if idInput in keyWords:
print "%s is keyword fot Python!" % idInput
else:
lenNum = len(idInput)
if(1 == lenNum):
if(idInput in charForId and idInput != "_"):
print "%s is legal identifier for Python!" % idInput
else:

It's just "_"

        print "%s isn't legal identifier for Python!" % idInput

else:  
    if(idInput[0:1] in charForId):  
        legalstring = charForId + numForId  
        for item in idInput[1:]:  
            if (item not in legalstring):  
                print "%s isn't legal identifier for Python!" % idInput  
                sys.exit(0)  
        print "%s is legal identifier for Python!2" % idInput  
    else:  
        print "%s isn't legal identifier for Python!3" % idInput