pytyon 带有重复的全排列

1021次阅读  |  发布于5年以前

复制代码 代码如下:

from sys import argv
script, start, end = argv
vis = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
ans = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
def dfs(cur, m):
ans[cur] = m
if cur == int(end) - int(start) + 1:
for i in xrange(int(start), int(end) + 1):
print ans[i],
return
cur = cur + 1
for i in xrange(int(start), int(end) + 1):
dfs(cur, i)
print
dfs(0, start)

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