最近好多分享这个问题的代码，题目说的是用面向对象或者函数式编程，下面是PYTHON的实现示例

复制代码 代码如下:

!/usr/bin/python

encoding:utf8

'''
The Game of "FizzBuzzWhizz"
author : wang.jiankui89@gmail.com
mobile : 130-2199-5152
'''
import sys

class teacher:
def init(self, student_num):
self.student_num = student_num

def gameStart(self, numList):  
    for i in range (1, self.student_num + 1):  
        stu = student(i)   
        print stu.answer(numList)

class student:
def init(self, my_num):
self.my_num = my_num

def judgeMod(self, numList):  
    modRes = ""  
    for num in numList:  
        if self.my_num % num == 0:  
            modRes += rule[num]  
    return modRes if modRes else self.my_num

def judgeContain(self, first_num):  
    conRes = ""  
    if str(first_num) in str(self.my_num) :  
        conRes = rule[first_num]  
    return conRes

def answer(self, numList):  
    conRes = self.judgeContain(numList[0])  
    return conRes if conRes else self.judgeMod(numList)

def getOps():
'''parse options'''
if len(sys.argv) != 4 :
print "use as fizzBuzzWhizz.py [0-9] [0-9] [0-9]"
sys.exit()
else:
first_num = int(sys.argv[1])
second_num = int(sys.argv[2])
third_num = int(sys.argv[3])
return first_num, second_num, third_num

def main():
first_num, second_num, third_num = getOps()
global rule
rule = {first_num:"Fizz", second_num:"Buzz", third_num:"Whizz"}

student_num = 100  

tea = teacher(100)  
tea.gameStart( (first_num, second_num, third_num) )

if name == "main":
main()