Python实现从url中提取域名的几种方法

从url中找到域名,首先想到的是用正则，然后寻找相应的类库。用正则解析有很多不完备的地方，url中有域名，域名后缀一直在不断增加等。通过google查到几种方法，一种是用Python中自带的模块和正则相结合来解析域名，另一种是使第三方用写好的解析模块直接解析出域名。

要解析的url

复制代码 代码如下:

urls = ["http://meiwen.me/src/index.html",
"http://1000chi.com/game/index.html",
"http://see.xidian.edu.cn/cpp/html/1429.html",
"https://docs.python.org/2/howto/regex.html",
"""https://www.google.com.hk/search?client=aff-cs-360chromium&hs;=TSj&q;=url%E8%A7%A3%E6%9E%90%E5%9F%9F%E5%90%8Dre&oq;=url%E8%A7%A3%E6%9E%90%E5%9F%9F%E5%90%8Dre&gs;_l=serp.3...74418.86867.0.87673.28.25.2.0.0.0.541.2454.2-6j0j1j1.8.0....0...1c.1j4.53.serp..26.2.547.IuHTj4uoyHg""",
"file:///D:/code/echarts-2.0.3/doc/example/tooltip.html",
"http://api.mongodb.org/python/current/faq.html#is-pymongo-thread-safe",
"https://pypi.python.org/pypi/publicsuffix/",
"http://127.0.0.1:8000"
]

使用urlparse+正则的方式

复制代码 代码如下:

import re
from urlparse import urlparse

topHostPostfix = (
'.com','.la','.io','.co','.info','.net','.org','.me','.mobi',
'.us','.biz','.xxx','.ca','.co.jp','.com.cn','.net.cn',
'.org.cn','.mx','.tv','.ws','.ag','.com.ag','.net.ag',
'.org.ag','.am','.asia','.at','.be','.com.br','.net.br',
'.bz','.com.bz','.net.bz','.cc','.com.co','.net.co',
'.nom.co','.de','.es','.com.es','.nom.es','.org.es',
'.eu','.fm','.fr','.gs','.in','.co.in','.firm.in','.gen.in',
'.ind.in','.net.in','.org.in','.it','.jobs','.jp','.ms',
'.com.mx','.nl','.nu','.co.nz','.net.nz','.org.nz',
'.se','.tc','.tk','.tw','.com.tw','.idv.tw','.org.tw',
'.hk','.co.uk','.me.uk','.org.uk','.vg', ".com.hk")

regx = r'[^\.]+('+'|'.join([h.replace('.',r'\.') for h in topHostPostfix])+')$'
pattern = re.compile(regx,re.IGNORECASE)

print "--"*40
for url in urls:
parts = urlparse(url)
host = parts.netloc
m = pattern.search(host)
res = m.group() if m else host
print "unkonw" if not res else res