Python 两个列表的差集、并集和交集实现代码

1084次阅读  |  发布于5年以前

①差集
方法一:


    if __name__ == '__main__':
        a_list = [{'a' : 1}, {'b' : 2}, {'c' : 3}, {'d' : 4}, {'e' : 5}]
        b_list = [{'a' : 1}, {'b' : 2}]
        ret_list = []
        for item in a_list:
            if item not in b_list:
                ret_list.append(item)
        for item in b_list:
            if item not in a_list:
                ret_list.append(item)
        print(ret_list)

执行结果:

方法二:


    if __name__ == '__main__':
        a_list = [{'a' : 1}, {'b' : 2}, {'c' : 3}, {'d' : 4}, {'e' : 5}]
        b_list = [{'a' : 1}, {'b' : 2}]
        ret_list = [item for item in a_list if item not in b_list] + [item for item in b_list if item not in a_list]
        print(ret_list)

执行结果:

方法三:


    if __name__ == '__main__':
        a_list = [1, 2, 3, 4, 5]
        b_list = [1, 4, 5]
        ret_list = list(set(a_list)^set(b_list))
        print(ret_list)

执行结果:

注:此方法中,两个list中的元素不能为字典

②并集


    if __name__ == '__main__':
        a_list = [1, 2, 3, 4, 5]
        b_list = [1, 4, 5]
        ret_list = list(set(a_list).union(set(b_list)))
        print(ret_list)

执行结果:

注:此方法中,两个list中的元素不能为字典

③交集


    if __name__ == '__main__':
        a_list = [1, 2, 3, 4, 5]
        b_list = [1, 4, 5]
        ret_list = list((set(a_list).union(set(b_list)))^(set(a_list)^set(b_list)))
        print(ret_list)

执行结果:

注:此方法中,两个list中的元素不能为字典

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