python使用正则表达式检测密码强度源码分享

994次阅读  |  发布于5年以前

复制代码 代码如下:

encoding=utf-8

-------------------------------------------------------------------------------

Name: 模块1

Purpose:

Author: Administrator

Created: 10-06-2014

Copyright: (c) Administrator 2014

Licence:

-------------------------------------------------------------------------------

import re
def checklen(pwd):
return len(pwd)>=8
def checkContainUpper(pwd):
pattern = re.compile('[A-Z]+')
match = pattern.findall(pwd)
if match:
return True
else:
return False
def checkContainNum(pwd):
pattern = re.compile('[0-9]+')
match = pattern.findall(pwd)
if match:
return True
else:
return False
def checkContainLower(pwd):
pattern = re.compile('[a-z]+')
match = pattern.findall(pwd)
if match:
return True
else:
return False
def checkSymbol(pwd):
pattern = re.compile('([^a-z0-9A-Z])+')
match = pattern.findall(pwd)
if match:
return True
else:
return False
def checkPassword(pwd):

判断密码长度是否合法

lenOK=checklen(pwd)  
#判断是否包含大写字母  
upperOK=checkContainUpper(pwd)  
#判断是否包含小写字母  
lowerOK=checkContainLower(pwd)  
#判断是否包含数字  
numOK=checkContainNum(pwd)  
#判断是否包含符号  
symbolOK=checkSymbol(pwd)  
print(lenOK)  
print(upperOK)  
print(lowerOK)  
print(numOK)  
print(symbolOK)  
return (lenOK and upperOK and lowerOK and numOK and symbolOK)

def main():
if checkPassword('Helloworld#123'):
print('检测通过')
else:
print('检测未通过')

if name == 'main':
main()

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