Python实现方便使用的级联进度信息实例

本文实例讲述了Python实现方便使用的级联进度信息的方法。分享给大家供大家参考。具体实现方法如下：

    class StepedProgress:
      '''方便显示进度的级联进度信息。
      '''
      def __init__(self, stockPercent=[1], parentProgress=None):
        self.percent = 0
        self.info = ''
        self.subProgress = []
        self.cur_running_process = 0
        self.stockPercent = stockPercent
        self.parentProgress = parentProgress
        # 重新计算进度比，防止初始化时的值加起来不是1
        w = 0.0
        for p in self.stockPercent:
          w += p
        for i in range(0, len(stockPercent)):
          stockPercent[i] = stockPercent[i]/w
        # 初始化子进度
        if len(stockPercent) == 1:
          self.subProgress = None
        else:
          for p in self.stockPercent:
            self.subProgress.append(StepedProgress(parentProgress=self))
      def subprogress(self, index):
        if index >= self.subcount():
          return self.subProgress[self.subcount()-1]
        elif index < self.cur_running_process:
          return self.subProgress[self.cur_running_process]
        else:
          self.cur_running_process = index
          return self.subProgress[index]
      def subcount(self):
        return len(self.subProgress)
      def notifyParentProgress(self, percent, info=None):
        new_percent = 0.0
        for i in range(0, self.cur_running_process):
          new_percent += self.stockPercent[i]
        new_percent += percent/100.0 * self.stockPercent[self.cur_running_process]
        new_percent *= 100.0
        self.notifyProgress(new_percent, info)
      def notifyProgress(self, percent, info=None):
        if percent > self.percent:
          self.percent = percent
        if info is not None:
          self.info = info
        if self.parentProgress is not None:
          self.parentProgress.notifyParentProgress(percent, info)
        else:
          print self.info[:77].ljust(80, '.'), "[%0.1f%%]"%self.percent
    if __name__ == "__main__":
      s = StepedProgress([60, 40])
      s.notifyProgress(10, 'aaa')
      s1 = s.subprogress(0)
      s1.notifyProgress(50, 'bbb')
      s3 = s.subprogress(1)
      s3 = StepedProgress([1, 1], parentProgress=s3.parentProgress) #级联子进度
      s3.notifyProgress(20, 'ddd')
      s4 = s3.subprogress(0)
      s4.notifyProgress(50, 'eee')
      s5 = s3.subprogress(1)
      s5.notifyProgress(50, 'fff')

输出结果：

aaa............................................................................. [10.0%]
bbb............................................................................. [30.0%]
ddd............................................................................. [68.0%]
eee............................................................................. [70.0%]
fff............................................................................. [90.0%]

希望本文所述对大家的Python程序设计有所帮助。