python实现将英文单词表示的数字转换成阿拉伯数字的方法

本文实例讲述了python实现将英文单词表示的数字转换成阿拉伯数字的方法。分享给大家供大家参考。具体实现方法如下：

    import re
    _known = {
      'zero': 0,
      'one': 1,
      'two': 2,
      'three': 3,
      'four': 4,
      'five': 5,
      'six': 6,
      'seven': 7,
      'eight': 8,
      'nine': 9,
      'ten': 10,
      'eleven': 11,
      'twelve': 12,
      'thirteen': 13,
      'fourteen': 14,
      'fifteen': 15,
      'sixteen': 16,
      'seventeen': 17,
      'eighteen': 18,
      'nineteen': 19,
      'twenty': 20,
      'thirty': 30,
      'forty': 40,
      'fifty': 50,
      'sixty': 60,
      'seventy': 70,
      'eighty': 80,
      'ninety': 90
      }
    def spoken_word_to_number(n):
      """Assume n is a positive integer".
    assert _positive_integer_number('nine hundred') == 900
    assert spoken_word_to_number('one hundred') == 100
    assert spoken_word_to_number('eleven') == 11
    assert spoken_word_to_number('twenty two') == 22
    assert spoken_word_to_number('thirty-two') == 32
    assert spoken_word_to_number('forty two') == 42
    assert spoken_word_to_number('two hundred thirty two') == 232
    assert spoken_word_to_number('two thirty two') == 232
    assert spoken_word_to_number('nineteen hundred eighty nine') == 1989
    assert spoken_word_to_number('nineteen eighty nine') == 1989
    assert spoken_word_to_number('one thousand nine hundred and eighty nine') == 1989
    assert spoken_word_to_number('nine eighty') == 980
    assert spoken_word_to_number('nine two') == 92 # wont be able to convert this one
    assert spoken_word_to_number('nine thousand nine hundred') == 9900
    assert spoken_word_to_number('one thousand nine hundred one') == 1901
    """
      n = n.lower().strip()
      if n in _known:
        return _known[n]
      else:
        inputWordArr = re.split('[ -]', n)
      assert len(inputWordArr) > 1 #all single words are known
      #Check the pathological case where hundred is at the end or thousand is at end
      if inputWordArr[-1] == 'hundred':
        inputWordArr.append('zero')
        inputWordArr.append('zero')
      if inputWordArr[-1] == 'thousand':
        inputWordArr.append('zero')
        inputWordArr.append('zero')
        inputWordArr.append('zero')
      if inputWordArr[0] == 'hundred':
        inputWordArr.insert(0, 'one')
      if inputWordArr[0] == 'thousand':
        inputWordArr.insert(0, 'one')
      inputWordArr = [word for word in inputWordArr if word not in ['and', 'minus', 'negative']]
      currentPosition = 'unit'
      prevPosition = None
      output = 0
      for word in reversed(inputWordArr):
        if currentPosition == 'unit':
          number = _known[word]
          output += number
          if number > 9:
            currentPosition = 'hundred'
          else:
            currentPosition = 'ten'
        elif currentPosition == 'ten':
          if word != 'hundred':
            number = _known[word]
            if number < 10:
              output += number*10
            else:
              output += number
          #else: nothing special
          currentPosition = 'hundred'
        elif currentPosition == 'hundred':
          if word not in [ 'hundred', 'thousand']:
            number = _known[word]
            output += number*100
            currentPosition = 'thousand'
          elif word == 'thousand':
            currentPosition = 'thousand'
          else:
            currentPosition = 'hundred'
        elif currentPosition == 'thousand':
          assert word != 'hundred'
          if word != 'thousand':
            number = _known[word]
            output += number*1000
        else:
          assert "Can't be here" == None
      return(output)

希望本文所述对大家的Python程序设计有所帮助。