python比较2个xml内容的方法

本文实例讲述了python比较2个xml内容的方法。分享给大家供大家参考。具体分析如下：

    from xml.etree import ElementTree 
    OK=True 
    main_pid = 10000 
    loop_depth = 0 
    def compare_xml(left, right, key_info='.'):
      global loop_depth 
      loop_depth += 1 
      if loop_depth == 1: print 
      if left.tag != right.tag: 
        print_diff(main_pid, key_info, 'difftag', left.tag, right.tag)
        return 
      if left.text != right.text: 
        print_diff(main_pid, key_info, 'difftext', left.text, right.text)
        return 
      leftitems = dict(left.items()) 
      rightitems = dict(right.items()) 
      for k,v in leftitems.items(): 
        if k not in rightitems: 
          s = '%s/%s' % (key_info, left.tag) 
          print_diff(main_pid, s, 'lostattr', k, "")
      for k,v in rightitems.items(): 
        if k not in leftitems: 
          s = '%s/%s' % (key_info, right.tag) 
          print_diff(main_pid, s, 'extraattr', "", k)
      leftnodes = left.getchildren() 
      rightnodes = right.getchildren() 
      leftlen = len(leftnodes) 
      rightlen = len(rightnodes) 
      if leftlen != rightlen: 
        s = '%s/%s' % (key_info, right.tag)
        print_diff(main_pid, s, 'difflen', leftlen, rightlen)
        return 
      l = leftlen<rightlen and leftlen or rightlen
      d = {} 
      for i in xrange(l):     
        node=leftnodes[i] 
        if node.tag not in d: 
          d[node.tag] = 1 
          tag = node.tag 
        else: 
          tag = node.tag + str(d[node.tag])
          d[node.tag] += 1 
        s = '%s/%s' % (key_info, tag) 
        compare_xml(leftnodes[i], rightnodes[i], s)
    def print_diff(main_pid, key_info, msg, base_type, test_type):
      global OK 
      info = u'[ %-5s ] %s -> %-40s [ %s != %s ]'%(msg.upper(), main_pid, key_info.strip('./'), base_type, test_type)
      print info.encode('gbk')
      OK = False

调用：

    if __name__ == '__main__': 
      s1 = '''''<?xml version="1.0" encoding="UTF-8"?> \
         <employees> \ 
         <employee id = '1'> \ 
          <name>linux</name>\ 
          <age>30</age>\ 
         </employee>\ 
         <employee id = '2'> \ 
          <name>windows</name>\ 
          <age>20</age>\ 
         </employee>\ 
         </employees>'''  
      s2 = '''''<?xml version="1.0" encoding="UTF-8"?> \
         <employees> \ 
         <employee id = '3'> \ 
          <name>windows</name>\ 
          <age>20</age>\ 
         </employee>\ 
         <employee id = '4'> \ 
          <name>linux</name>\ 
          <age>30</age>\ 
         </employee>\ 
         </employees>'''  
      lroot = ElementTree.fromstring(s1) 
      rroot = ElementTree.fromstring(s2) 
      compare_xml(lroot, rroot)

希望本文所述对大家的Python程序设计有所帮助。