python实现数独算法实例

本文实例讲述了python实现数独算法的方法。分享给大家供大家参考。具体如下：

    # -*- coding: utf-8 -*-
    '''
    Created on 2012-10-5
    @author: Administrator
    '''
    from collections import defaultdict
    import itertools
    a = [
      [ 0, 7, 0, 0, 0, 0, 0, 0, 0], #0
      [ 5, 0, 3, 0, 0, 6, 0, 0, 0], #1
      [ 0, 6, 2, 0, 8, 0, 7, 0, 0], #2
      #
      [ 0, 0, 0, 3, 0, 2, 0, 5, 0], #3
      [ 0, 0, 4, 0, 1, 0, 3, 0, 0], #4
      [ 0, 2, 0, 9, 0, 5, 0, 0, 0], #5
      #
      [ 0, 0, 1, 0, 3, 0, 5, 9, 0], #6
      [ 0, 0, 0, 4, 0, 0, 6, 0, 3], #7
      [ 0, 0, 0, 0, 0, 0, 0, 2, 0], #8
    #  0, 1, 2, 3,|4, 5, 6,|7, 8
      ]
    #a = [
    #  [0, 0, 0, 0, 0, 0, 0, 0, 0], #0
    #  [0, 0, 0, 0, 0, 0, 0, 0, 0], #1
    #  [0, 0, 0, 0, 0, 0, 0, 0, 0], #2
    #  #
    #  [0, 0, 0, 0, 0, 0, 0, 0, 0], #3
    #  [0, 0, 0, 0, 0, 0, 0, 0, 0], #4
    #  [0, 0, 0, 0, 0, 0, 0, 0, 0], #5
    #  #
    #  [0, 0, 0, 0, 0, 0, 0, 0, 0], #6
    #  [0, 0, 0, 0, 0, 0, 0, 0, 0], #7
    #  [0, 0, 0, 0, 0, 0, 0, 0, 0], #8
    ##  0, 1, 2, 3,|4, 5, 6,|7, 8
    #  ]
    exists_d = dict((((h_idx, y_idx), v) for h_idx, y in enumerate(a) for y_idx , v in enumerate(y) if v))
    h_exist = defaultdict(dict)
    v_exist = defaultdict(dict)
    for k, v in exists_d.items():
     h_exist[k[ 0]][k[ 1]] = v
     v_exist[k[ 1]][k[ 0]] = v
    aa = list(itertools.permutations(range(1, 10), 9))
    h_d = {}
    for hk, hv in h_exist.items():
     x = filter(lambda x:all((x[k] == v for k, v in hv.items())), aa)
     x = filter(lambda x:all((x[vk] != v for vk , vv in v_exist.items() for k, v in vv.items() if k != hk)), x)
    # print x
     h_d[hk] = x
    def test(x, y):
     return all([y[i] not in [x_[i] for x_ in x] for i in range(len(y)) ])
    def test2(x):
     return len(set(x)) != 9
    s = set(range(9))
    sudokus = []
    for l0 in h_d[0 ]:
     for l1 in h_d[ 1]:
      if not test((l0,), l1):
       continue
      for l2 in h_d[ 2]:
       if not test((l0, l1), l2):
        continue
       # 1,2,3行 进行验证
       if test2([l0[ 0], l0[ 1], l0[ 2]
          , l1[ 0], l1[ 1], l1[ 2]
          , l2[ 0], l2[ 1], l2[ 2]
          ]) : continue   
       if test2([l0[ 3], l0[ 4], l0[ 5]
          , l1[ 3], l1[ 4], l1[ 5]
          , l2[ 3], l2[ 4], l2[ 5]
          ]) : continue   
       if test2([l0[ 6], l0[ 7], l0[ 8]
          , l1[ 6], l1[ 7], l1[ 8]
          , l2[ 6], l2[ 7], l2[ 8]
          ]) : continue   
       for l3 in h_d[ 3]:
        if not test((l0, l1, l2), l3):
         continue
        for l4 in h_d[ 4]:
         if not test((l0, l1, l2, l3), l4):
          continue
         for l5 in h_d[ 5]:
          if not test((l0, l1, l2, l3, l4), l5):
           continue
          # 4，5，6行 进行验证
          if test2([l3[ 0], l3[ 1], l3[ 2]
             , l4[ 0], l4[ 1], l4[ 2]
             , l5[ 0], l5[ 1], l5[ 2]
             ]) : continue   
          if test2([l3[ 3], l3[ 4], l3[ 5]
             , l4[ 3], l4[ 4], l4[ 5]
             , l5[ 3], l5[ 4], l5[ 5]
             ]) : continue   
          if test2([l3[ 6], l3[ 7], l3[ 8]
             , l4[ 6], l4[ 7], l4[ 8]
             , l5[ 6], l5[ 7], l5[ 8]
             ]) : continue   
          for l6 in h_d[ 6]:
           if not test((l0, l1, l2, l3, l4, l5,), l6):
            continue
           for l7 in h_d[ 7]:
            if not test((l0, l1, l2, l3, l4, l5, l6), l7):
             continue
            for l8 in h_d[ 8]:
             if not test((l0, l1, l2, l3, l4, l5, l6, l7), l8):
              continue
             # 7，8，9行 进行验证
             if test2([l6[ 0], l6[ 1], l6[ 2]
                , l7[0 ], l7[1 ], l7[2 ]
                , l8[0 ], l8[1 ], l8[2 ]
                ]) : continue   
             if test2([l6[ 3], l6[ 4], l6[ 5]
                , l7[3 ], l7[4 ], l7[5 ]
                , l8[3 ], l8[4 ], l8[5 ]
                ]) : continue   
             if test2([l6[ 6], l6[ 7], l6[ 8]
                , l7[6 ], l7[7 ], l7[8 ]
                , l8[6 ], l8[7 ], l8[8 ]
                ]) : continue   
             print l0
             print l1
             print l2
             print l3
             print l4
             print l5
             print l6
             print l7
             print l8
             sudokus.append((l0, l1, l2, l3, l4, l5, l6, l7, l8))

希望本文所述对大家的Python程序设计有所帮助。