浅谈Python中用datetime包进行对时间的一些操作

791次阅读  |  发布于5年以前

1. 计算给出两个时间之间的时间差


    import datetime as dt
    # current time
    cur_time = dt.datetime.today()
    # one day
    pre_time = dt.date(2016, 5, 20) # eg: 2016.5.20
    delta = cur_time - pre_time
    # if you want to get discrepancy in days
    print delta.days
    # if you want to get discrepancy in hours
    print delta.hours
    # and so on

2. 获取n天前的时间


    cur_time = dt.now()
    # previous n days
    pre_time = dt.timedelta(days=n)

3. 将给定的时间精确到天或者其他单位


    cur_time = dt.now()
    # get day of current time
    cur_day = cur_time.replace(hour=0, minute=0, second=0, mircrosecond=0)

4. 获取一连串的时间序列(返回list)


    cur_time = dt.datetime.today()
    datelist = [cur_time - dt.timedelta(days=x) for x in range(0, 100)]

或者


    import pandas as pd
    datelist = pd.date_range(pd.datetime.today(), periods=100).tolist()

5. 将时间字符串转化为datetime类型


    date_formate = "%Y-%m-%d" # year-month-day
    time = dt.strptime('2016-06-22', date_format)

6. 将时间类型转化为字符串类型


    time_str = dt.strftime("%Y-%m-%d", dt.now()) # return like "2016-06-22"

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