//数组arr1相对于arr2所没有的 const arr1 = [1, 2, 3, 4, 5, 8, 9] const arr2 = [5, 6, 7, 8, 9]; const diff = arr1.filter(item => !new Set(arr2).has(item)) console.log(diff) //[ 1, 2, 3, 4 ]
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