list 等分 n 组

>>> from math import ceil
>>> def divide_iter(lst, n):
      if n <= 0:
        yield lst
        return
      i, div = 0, ceil(len(lst) / n)
      while i < n:
        yield lst[i * div: (i + 1) * div]
        i += 1


>>> for group in divide_iter([1,2,3,4,5],2):
      print(group)


[1, 2, 3]
[4, 5]