Leetcode 链接
Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.
Example: Given a binary tree 1 / \ 2 3 / \ 4 5 Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3]. Note: The length of path between two nodes is represented by the number of edges between them.
找出二叉树中任意两个点之间的最远距离。
/** * Definition for a binary tree node. * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */ var levelRecord map[*TreeNode]int func diameterOfBinaryTree(root *TreeNode) int { levelRecord = make(map[*TreeNode]int) getLevel(root) // NOTE: we only check the all nodes' level once return helper(root) } func helper(root *TreeNode) int { if root == nil || (root.Left == nil && root.Right == nil) { return 0 } withoutRoot := max(helper(root.Left), helper(root.Right)) withRoot := levelRecord[root.Left] + levelRecord[root.Right] return max(withoutRoot, withRoot) } func getLevel(root *TreeNode) int { res := 0 if root != nil { res = max(getLevel(root.Left), getLevel(root.Right)) + 1 } levelRecord[root] = res return res } func max(a, b int) int { if a > b { return a } return b }
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