Leetcode 链接
Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
Note: A leaf is a node with no children.
Example: Given the below binary tree and sum = 22, 5 / \ 4 8 / / \ 11 13 4 / \ \ 7 2 1 return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.
判断是否存在一条从根节点到叶子节点的路径,该路径和为指定的数。
/** * Definition for a binary tree node. * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */ func find(root *TreeNode, tmp int, sum *int) bool { if root == nil { return false } tmp += root.Val if (root.Left == nil) && (root.Right == nil) { if tmp == *sum { return true } else { return false } } return find(root.Left, tmp, sum) || find(root.Right, tmp, sum) } func hasPathSum(root *TreeNode, sum int) bool { return find(root, 0, &sum) }
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